CGAL 5.5.3 - 2D Arrangements
Arrangement_on_surface_2/circular_arcs.cpp
// Constructing an arrangement of various circular arcs and line segments.
#include "arr_circular.h"
#include "arr_print.h"
int main() {
std::list<Curve> curves;
// Create a circle (C1) centered at the origin with squared radius 2.
curves.push_back(Curve(Circle(Rational_point(0, 0), Number_type(2))));
// Create a circle (C2) centered at (2, 3) with radius 3/2. Note that
// as the radius is rational we use a different curve constructor.
Number_type three_halves = Number_type(3) / Number_type(2);
curves.push_back(Curve(Rational_point(2, 3), three_halves));
// Create a segment (C3) of the line (y = x) with rational endpoints.
Segment s3 = Segment(Rational_point(-2, -2), Rational_point(2, 2));
curves.push_back(Curve(s3));
// Create a line segment (C4) with the same supporting line (y = x), but
// having one endpoint with irrational coordinates.
CoordNT sqrt_15 = CoordNT(0, 1, 15); // = sqrt(15)
curves.push_back(Curve(s3.supporting_line(),
Point(3, 3), Point(sqrt_15, sqrt_15)));
// Create a circular arc (C5) that is the upper half of the circle centered at
// (1, 1) with squared radius 3. Create the circle with clockwise orientation,
// so the arc is directed from (1 - sqrt(3), 1) to (1 + sqrt(3), 1).
Rational_point c5(1, 1);
Circle circ5(c5, 3, CGAL::CLOCKWISE);
CoordNT one_minus_sqrt_3(1, -1, 3);
CoordNT one_plus_sqrt_3(1, 1, 3);
Point s5(one_minus_sqrt_3, CoordNT(1));
Point t5(one_plus_sqrt_3, CoordNT(1));
curves.push_back(Curve(circ5, s5, t5));
// Create an arc (C6) of the unit circle, directed clockwise from
// (-1/2, sqrt(3)/2) to (1/2, sqrt(3)/2).
// The supporting circle is oriented accordingly.
Rational_point c6(0, 0);
Number_type half = Number_type(1) / Number_type(2);
CoordNT sqrt_3_div_2(Number_type(0), half, 3);
Point s6(-half, sqrt_3_div_2);
Point t6(half, sqrt_3_div_2);
curves.push_back(Curve(c6, 1, CGAL::CLOCKWISE, s6, t6));
// Create a circular arc (C7) defined by two endpoints and a midpoint,
// all having rational coordinates. This arc is the upper right
// quarter of a circle centered at the origin with radius 5.
curves.push_back(Curve(Rational_point(0, 5), Rational_point(3, 4),
Rational_point(5, 0)));
// Construct the arrangement of the curves and print its size.
Arrangement arr;
insert(arr, curves.begin(), curves.end());
print_arrangement_size(arr);
return 0;
}